-16x^2+6x+22=0

Solution for -16x^2+6x+22=0 equation:

-16x^2+6x+22=0

a = -16; b = 6; c = +22;
Δ = b2-4ac
Δ = 62-4·(-16)·22
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-38}{2*-16}=\frac{-44}{-32}
=1+3/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+38}{2*-16}=\frac{32}{-32}
=-1
$